ex9

TITLE Example 9.--Kinetically controlled oxidation of ferrous
                  iron. Decoupled valence states of iron.
SOLUTION_MASTER_SPECIES
Fe_di              Fe_di+2    0.0     Fe_di              55.847
Fe_tri             Fe_tri+3   0.0     Fe_tri             55.847
SOLUTION_SPECIES
Fe_di+2 = Fe_di+2
        log_k   0.0
Fe_tri+3 = Fe_tri+3
        log_k   0.0
#
# Fe+2 species
#
Fe_di+2 + H2O = Fe_diOH+ + H+
        log_k   -9.5
        delta_h 13.20   kcal
#
#... and also other Fe+2 species
#
Fe_di+2 + Cl- = Fe_diCl+
        log_k   0.14
Fe_di+2 + CO3-2 = Fe_diCO3
        log_k   4.38
Fe_di+2 + HCO3- = Fe_diHCO3+
        log_k   2.0
Fe_di+2 + SO4-2 = Fe_diSO4
        log_k   2.25
        delta_h 3.230   kcal
Fe_di+2 + HSO4- = Fe_diHSO4+
        log_k   1.08
Fe_di+2 + 2HS- = Fe_di(HS)2
        log_k   8.95
Fe_di+2 + 3HS- = Fe_di(HS)3-
        log_k   10.987
Fe_di+2 + HPO4-2 = Fe_diHPO4
        log_k   3.6
Fe_di+2 + H2PO4- = Fe_diH2PO4+
        log_k   2.7
Fe_di+2 + F- = Fe_diF+
        log_k   1.0
#
# Fe+3 species
#
Fe_tri+3 + H2O = Fe_triOH+2 + H+
        log_k   -2.19
        delta_h 10.4    kcal
#
#... and also other Fe+3 species
#
Fe_tri+3 + 2 H2O = Fe_tri(OH)2+ + 2 H+
        log_k   -5.67
        delta_h 17.1    kcal
Fe_tri+3 + 3 H2O = Fe_tri(OH)3 + 3 H+
        log_k   -12.56
        delta_h 24.8    kcal
Fe_tri+3 + 4 H2O = Fe_tri(OH)4- + 4 H+
        log_k   -21.6
        delta_h 31.9    kcal
2 Fe_tri+3 + 2 H2O = Fe_tri2(OH)2+4 + 2 H+
        log_k   -2.95
        delta_h 13.5    kcal
3 Fe_tri+3 + 4 H2O = Fe_tri3(OH)4+5 + 4 H+
        log_k   -6.3
        delta_h 14.3    kcal
Fe_tri+3 + Cl- = Fe_triCl+2
        log_k   1.48
        delta_h 5.6     kcal
Fe_tri+3 + 2 Cl- = Fe_triCl2+
        log_k   2.13
Fe_tri+3 + 3 Cl- = Fe_triCl3
        log_k   1.13
Fe_tri+3 + SO4-2 = Fe_triSO4+
        log_k   4.04
        delta_h 3.91    kcal
Fe_tri+3 + HSO4- = Fe_triHSO4+2
        log_k   2.48
Fe_tri+3 + 2 SO4-2 = Fe_tri(SO4)2-
        log_k   5.38
        delta_h 4.60    kcal
Fe_tri+3 + HPO4-2 = Fe_triHPO4+
        log_k   5.43
        delta_h 5.76    kcal
Fe_tri+3 + H2PO4- = Fe_triH2PO4+2
        log_k   5.43
Fe_tri+3 + F- = Fe_triF+2
        log_k   6.2
        delta_h 2.7     kcal
Fe_tri+3 + 2 F- = Fe_triF2+
        log_k   10.8
        delta_h 4.8     kcal
Fe_tri+3 + 3 F- = Fe_triF3
        log_k   14.0
        delta_h 5.4     kcal
PHASES
Goethite
        Fe_triOOH + 3 H+ = Fe_tri+3 + 2 H2O
        log_k   -1.0
END
SOLUTION 1
        pH  7.0
        pe 10.0  O2(g) -0.67
        Fe_di  0.1
        Na  10.
        Cl  10.  charge
EQUILIBRIUM_PHASES 1
        O2(g)           -0.67
RATES
Fe_di_ox
-start
10  Fe_di = TOT("Fe_di")
20  if (Fe_di <= 0) then goto 200
30  p_o2 = 10^(SI("O2(g)"))
40  moles = (2.91e-9 + 1.33e12 * (ACT("OH-"))^2 * p_o2) * Fe_di * TIME
200 SAVE moles
-end
KINETICS 1
Fe_di_ox
        -formula  Fe_di  -1.0  Fe_tri  1.0
        -steps 100 400 3100 10800 21600 5.04e4 8.64e4 1.728e5 1.728e5 1.728e5 1.728e5
INCREMENTAL_REACTIONS true
SELECTED_OUTPUT
        -file ex9.sel
        -reset false
USER_PUNCH
-headings Days  Fe(2)  Fe(3)  pH  si_goethite
10 PUNCH SIM_TIME/3600/24 TOT("Fe_di")*1e6, TOT("Fe_tri")*1e6, -LA("H+"), SI("Goethite")
END